Diagram drawn below is for questions 11, 12 and 13.

If we take AB = x then AD = 2x and BD = x Ö3 by ( 30^{0}  60^{0}  90^{0} )
Theorem. Again by ( 30^{0}  60^{0}  90^{0} ) Theorem BC = 2 x Ö3 and DC = 3 x.
Hence AD < BC.
Hence B.

AB < CD.
Hence B.

AD < CD.
Hence B.
The following diagram is common for problems numbered 14 and 15.

Side AB is opposite the largest angle 3x^{0}, hence it is the largest side,
i.e. AB > AC.
Hence A.
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Index
Test 3
Section 1 : Verbal
Section
Section 2 : Quantitative
Section
Section 3 : Analytical
Section
Section 4 : Quantitative
Section
Section 5 : Verbal
Section
Section 6 : Analytical
Section
Section 7 : Quantitative
Section
Answer key to Test 3
Answer Explanation To Test 3
Section 1 : Verbal
Section
Section 2 : Quantitative
Section
Section 3 : Analytical
Section
Section 4 : Quantitative
Section
Section 5 : Verbal
Section
Section 6 : Analytical
Section
Section 7 : Quantitative
Section
Test 4
