4. From the given diagram it is easy to see that a = -1; b = 1 and c = 3
   (Note: a, b, c are integers)

   \ b - a = 1- (-1) = 1 + 1 = 2 and b - c = 1 - 3 = -2 and 2 > -2.

   Hence A.

   OR

   One can even conclude without calculation that b > a (since b is to the right of a), i.e. b - c < 0 i.e. negative.

   \ b - 1 > b - c

   Hence A .

5. ( x + y)² = x² + 2xy + y²

   Hence x² + 2xy + y² > x² + y²

   Since the extra term 2xy on the left hand side of the inequality in positive.
   ( \ x > 0 and y > 0).

   Hence A.

6. Even if the student does not know much about polygons he can consider two very common regular polygons namely equilateral triangle whose exterior angle is 120⁰ and a square whose exterior angle is 90⁰ and arrive at the conclusion that as the number of sides increases (from 3 to 4) the exterior angle decreases from 120⁰ to 90⁰). Hence the exterior angle of a regular pentagon (five sides) will be more than an exterior angle of a regular hexagon ( 6 sides).

   Hence A.

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Index

Test 1

Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Verbal Section
Answer Key To Test 1

Answer Explanation To
Test 1
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Verbal Section