 The two equal sides of the triangle gives y = 59^{0} and 59^{0} + 59^{0} = 118^{0}, so that x = 180  118 = 62^{0}.
Hence A.

Hence B.
 x and y are both positive, therefore their square roots are real numbers. On squaring the numbers under both the columns we have
Hence A.

Hence B.
 The two equal sides of the triangle gives us y = 61^{0} and its supplementary
angle z = 119^{0}. The third angle of the triangle
x = 180  2 ´ 61 = 180  122 = 58^{0}. Hence x + y = 58 + 61 = 119.
Hence C.
 Ð q = 91^{0} (vertically opp. Ð ).
\ Ð p = 180^{0}  91^{0} = 89^{0} (Linear pairs are supplementary)
Ð p < Ð q
Ð p + Ð r < Ð q Ð r
Hence B.
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Index
Test 2
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Answer Key To Test 2
Answer Explanation To Test 2
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Test
3
