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  1. The two equal sides of the triangle gives y = 590 and 590 + 590 = 1180, so that x = 180 - 118 = 620.
    Hence A.


  2. Hence B.

  3. x and y are both positive, therefore their square roots are real numbers. On squaring the numbers under both the columns we have
    Hence A.



  4. Hence B.

  5. The two equal sides of the triangle gives us y = 610 and its supplementary angle z = 1190. The third angle of the triangle x = 180 - 2 61 = 180 - 122 = 580. Hence x + y = 58 + 61 = 119.
    Hence C.

  6. Ð q = 910 (vertically opp. Ð ).
    \ Ð p = 1800 - 910 = 890 (Linear pairs are supplementary)
    Ð p < Ð q
    Ð p + Ð r < Ð q Ð r
    Hence B.

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Index

Test 2

Section 1 : Verbal Section

Section 2 : Quantitative Section

Section 3 : Analytical Section

Section 4 : Quantitative Section

Section 5 : Verbal Section

Section 6 : Analytical Section

Answer Key To Test 2

Answer Explanation To Test 2
Section 1 : Verbal Section

Section 2 : Quantitative Section

Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section

Section 6 : Analytical Section

Test 3




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