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 The two equal sides of the triangle gives y = 590 and 590 + 590 = 1180, so that x = 180 - 118 = 620. Hence A. Hence B. x and y are both positive, therefore their square roots are real numbers. On squaring the numbers under both the columns we have Hence A. Hence B. The two equal sides of the triangle gives us y = 610 and its supplementary angle z = 1190. The third angle of the triangle x = 180 - 2 ´ 61 = 180 - 122 = 580. Hence x + y = 58 + 61 = 119. Hence C. Ð q = 910 (vertically opp. Ð ). \ Ð p = 1800 - 910 = 890 (Linear pairs are supplementary) Ð p < Ð q Ð p + Ð r < Ð q Ð r Hence B. Test 2 Section 1 : Verbal Section Section 2 : Quantitative Section Section 3 : Analytical Section Section 4 : Quantitative Section Section 5 : Verbal Section Section 6 : Analytical Section Answer Key To Test 2 Answer Explanation To Test 2 Section 1 : Verbal Section Section 2 : Quantitative Section Section 3 : Analytical Section Section 4 : Quantitative Section Section 5 : Verbal Section Section 6 : Analytical Section Test 3