 From the diagram it can be seen that the width of the toilet is the difference between the widths of the bedroom and kitchen, i.e. ( 12’  8’ = 4’ ). The length of the toilet is equal to the length of the bathroom minus the difference between the lengths of the hall and bedroom is = 8’  ( 16’  12 ’ ) = 8’  4’ = 4’ .
Hence the dimensions are 4’ ´ 4’ .
Hence B.
 Total Area of the flat
a) Balcony ( 10 ´ 4 ) + Hall & Bedroom ( 16 ´ 22 ) = 392 sq. ft.

Hence B.
 Perimeter of the L shaped Hall cum dining room is (starting downwards from the top left hand corner )
16 + ( 10 + 12 ) + ( 8  4 ) + 12 + 12 + 10 = 76’
Hence C.
 Area of hall cum dining room = 16 ´ ( 10 + 12 )  ( 12 ´ 12 ) = 352  144 = 208.
Total area of flat = 560 sq. ft ( from answer no.22)
Hence D.
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Index
Test 2
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Answer Key To Test 2
Answer Explanation To Test 2
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Test
3
