
If x^{2} + 4x + 4 = 0
then ( x + 2 )^{2} = 0
i.e. x + 2 = 0
i.e. x = 2
Canceling the common terms x^{2} + 9
6x 6x
6(2) 6 (2)
12 12
Hence B.

( 1.1 )" ( 0.89 )^{89}
When any number greater than one, is raised to any positive integral power, its value increases whereas any number less than one raised to a similar power decreases. 1.1^{3} > 1.12 > 1.1 but (0.89)^{3} < (0.89)^{2} < 0.89
Hence A.

12x + 4y = 8
Multiplying the whole equation by
9x + 3y = 6
Hence C.
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Index
Test 3
Section 1 : Verbal
Section
Section 2 : Quantitative
Section
Section 3 : Analytical
Section
Section 4 : Quantitative
Section
Section 5 : Verbal
Section
Section 6 : Analytical
Section
Section 7 : Quantitative
Section
Answer key to Test 3
Answer Explanation To Test 3
Section 1 : Verbal
Section
Section 2 : Quantitative
Section
Section 3 : Analytical
Section
Section 4 : Quantitative
Section
Section 5 : Verbal
Section
Section 6 : Analytical
Section
Section 7 : Quantitative
Section
Test 4
