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  1. Length of the uncommon region if least overlap occurs

    = Circumference - Length of the greater arc

    = 30 - 24

    = 6

    Length of the least overlap region

    = 16 - 6

    = 10

    Ans : B

  2. Painted area = Area of four walls

    100 = 4x2

    x2 = 25 where ‘x’ is side of square

    x = 5

    Volume of cube

    = x3

    = 5 ´ 5 ´ 5

    = 125

    Ans : D

  3. Let the integers be 3x and 2x.

    3x - 2x = 36

    x = 36

    The smallest integer is 72.

    Ans : A

  4. Since the line segment from B to A is broken, the Pythagorean method for determining length BA cannot be used.

    Also since each segment is parallel either to OA or OB, the total length from B to A must necessarily be (a + g).

    Ans : E

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Index

PART IV

Drill :

Section 1 : Verbal Reasoning
Section 2 : Mathematical Reasoning
Section 3 : Verbal Reasoning
Section 4 : Mathematical Reasoning
Section 5 : Reading Comprehension
Section 6 : Mathematical Reasoning
Section 7 : Verbal Reasoning

Answer Explanation To The Drill
Section 1 : Verbal Reasoning
Section 2 : Mathematical Reasoning
Section 3 : Verbal Reasoning
Section 4 : Mathematical Reasoning
Section 5 : Reading Comprehension
Section 6 : Mathematical Reasoning
Section 7 : Verbal Reasoning

Test 1

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