Illustration

Solve the right triangle ABC, if hypotenuse c = 6 and b = 3.

Solution

We have a²=c² - b²\ a²=6²-b² \ a² = (6)² - (3)² \ a²=27

(II) Two sides other than hypotenuse being given

Illustration

Solve the right triangle PQR, Given that r = 8, p = 5.

Solution :

(III) One angle (other than right angle) and its opposite side being known.

Solve triangle LMN, Ð M = 90⁰, Ð L = 30⁰ and l = 10

Solution : In triangle LMN, Ð N = 90⁰ - Ð L \ Ð N = 90⁰ - 30⁰ = 60⁰

(IV) One angle (other than right angle) and its adjacent side is being given.

Index

3. 1 Solving Right Triangles
3. 2 Law of Cosines
3. 3 Law of Sines
3. 4 The Ambiguous Case of Law of Sines
3. 5 Areas of Triangles
Supplementary Problems

Chapter 4