Example 13

Find the equation of the line having slope -2/3 and passes through (2 , - 5).

Solution :

y - y₁ = m ( x - x₁)

\ y - (-5) = (x - 2)

\ y + 5 = (x - 2)

\ 3 (y + 5) = 2 (x - 2)

\ 3y + 15 = 2x + 4

\ 2x + 3y + 11 = 0 ( general form )

Example 14

Find the equation of the line having slope and which crosses y-axis at 4.

Solution :

y = mx + c

y = x + 4

\ 3y = - 4x + 12

\ 4x + 3y - 12 = 0 (general form)

Index

Introduction

1.1 Functions And Mapping
1.2 Functions, Their Graphs and Classification
1.3 Rules for Drawing the Graph of a Curve
1.4 Classification of Functions
1.5 Standard Forms for the equation of a straight line
1.6 Circular Function and Trigonometry

Chapter 2