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1. D ADE is isosceles ( given )

2. \ x = 300

\ exterior angle = 30 + 30 = 600

Also D ADC is isosceles (given )

\ Ð ACD = y0

\ y + y + 60 = 1800 ( angles of D ADC )

\ y = 600

\ D ADC is equilateral

\ AC = DC

But DC + ED ( given )

\ AC = ED

Hence C.

3. From ( 13 ) above w = 600

Also in D ABC, z = 600

Since AC = DE = AB = BC

i.e. since D ABC is also equilateral

\ w = z

Hence C.

4. From ( 13 ) x = 300 and y = 600

\ x + y = 900

Hence C.



Test 4
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Analytical Section
Answer key to Test 4

Answer Explanation To Test 4
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Analytical Section

PART I To The Students