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1. Given n ! = n ( n - 1 ) ( n - 2 ) ............ ´ 4 ´ 3 ´ 2 ´ 1

\ ( n + 1 ) ! = ( n + 1 ) ( n ) ( n - 1 ) ( n - 2 ) ( n - 3 ) ..... ´ 3 ´ 2 ´ 1

( n - 1 ) ! = ( n - 1 ) ( n - 2 ) ( n - 3 ) ......... ´ 3 ´ 2 ´ 1

From above

( n + 1 ) ! = ( n + 1 ) ( n ) ( n - 1 ) !       OR

\ n ( n + 1 ) = 20

But n and n + 1 are consecutive integers whose product is 20.

Hence n = 4 and n + 1 = 5.

Hence E

2. The area of the passage can best be worked out by subtracting the areas of both toilet and bathroom from the area between bedroom and kitchen.

9 ´ 7 - ( 3 ´ 4 + 4 ´ 5 ) = 63 - ( 12 + 20 )

= 63 - 32

= 31 sq. ft.

Hence C.

3. The kitchen area is 6’ ´ 9’ = 54 sq. ft.

Whereas the bedroom area = 9’ ´ 9’ = 81 sq. ft.

Hence the required fraction is

Hence D.

4. Bedroom area = 9’ ´ 9’ = 81 sq. ft.

Hall area = 16’ ´ 9’ = 10 sq. ft.

Hence the required fraction is

Hence C.

5. Hence D.



Test 4
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Analytical Section
Answer key to Test 4

Answer Explanation To Test 4
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Analytical Section

PART I To The Students