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  1. Given n ! = n ( n - 1 ) ( n - 2 ) ............ 4 3 2 1

    \ ( n + 1 ) ! = ( n + 1 ) ( n ) ( n - 1 ) ( n - 2 ) ( n - 3 ) ..... 3 2 1

    ( n - 1 ) ! = ( n - 1 ) ( n - 2 ) ( n - 3 ) ......... 3 2 1

    From above

    ( n + 1 ) ! = ( n + 1 ) ( n ) ( n - 1 ) !       OR

          

    \ n ( n + 1 ) = 20

    But n and n + 1 are consecutive integers whose product is 20.

    Hence n = 4 and n + 1 = 5.

    Hence E

  2. The area of the passage can best be worked out by subtracting the areas of both toilet and bathroom from the area between bedroom and kitchen.

    9 7 - ( 3 4 + 4 5 ) = 63 - ( 12 + 20 )

    = 63 - 32

    = 31 sq. ft.

    Hence C.

  3. The kitchen area is 6 9 = 54 sq. ft.

    Whereas the bedroom area = 9 9 = 81 sq. ft.

    Hence the required fraction is

    Hence D.

  4. Bedroom area = 9 9 = 81 sq. ft.

    Hall area = 16 9 = 10 sq. ft.

    Hence the required fraction is

    Hence C.

  5. Hence D.




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Index

Test 4
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Analytical Section
Answer key to Test 4

Answer Explanation To Test 4
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Analytical Section

PART I To The Students