1. Length of the uncommon region if least overlap occurs

   = Circumference - Length of the greater arc

   = 30 - 24

   = 6

   Length of the least overlap region

   = 16 - 6

   = 10

   Ans : B

2. Painted area = Area of four walls

   100 = 4x2

   x² = 25 where ‘x’ is side of square

   x = 5

   Volume of cube

   = x³

   = 5 ´ 5 ´ 5

   = 125

   Ans : D

3. Let the integers be 3x and 2x.

   3x - 2x = 36

   x = 36

   The smallest integer is 72.

   Ans : A

4. Since the line segment from B to A is broken, the Pythagorean method for determining length BA cannot be used.

   Also since each segment is parallel either to OA or OB, the total length from B to A must necessarily be (a + g).

   Ans : E

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Index

PART IV

Drill :

Section 1 : Verbal Reasoning
Section 2 : Mathematical Reasoning
Section 3 : Verbal Reasoning
Section 4 : Mathematical Reasoning
Section 5 : Reading Comprehension
Section 6 : Mathematical Reasoning
Section 7 : Verbal Reasoning

Answer Explanation To The Drill
Section 1 : Verbal Reasoning
Section 2 : Mathematical Reasoning
Section 3 : Verbal Reasoning
Section 4 : Mathematical Reasoning
Section 5 : Reading Comprehension
Section 6 : Mathematical Reasoning
Section 7 : Verbal Reasoning

Test 1