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Example 37

Evaluate

Solution : Let cos x = t

then -sin x dx = dt

\ sin x dx = -dt

Example 38

Evaluate

Solution : Let x2 = t

then 2x dx = dt

Again put sint t = u, then cos t dt = du

Example 39

Evaluate

Solution : Let 1 + x2 = t

then 2x dx = dt

\ x dx = ˝ dt


Example 40

Evaluate

Solution :

Example 41

Evaluate

Solution :

Let cos x + sin x = t then (-sin x + cos x) dx = dt

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Index

6.1 Anti-derivatives (indefinite Integral)
6.2 Integration Of Some Trignometric Functions
6.3 Methods Of Integration
6.4 Substitution And Change Of Variables
6.5 Some Standard Substitutions
6.6 Integration By Parts
6.7 Integration By Partial Fractions

Chapter 7





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