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i.e. A (D ABC ) = A ( D DBC )
Bases being the same,.e. common BC, the larger D DBC will have a greater height DN compared to AM of smaller D ABC.
DN = Shortest distance of D from BC
AM = Shortest distance of A from BC
DN > AM
Diagram drawn below is for 12 to 15.
GivenÐ E = 300 and AB = BC = CD = DE = AD.
Diagonal AC of parallelogram ABCD divides it into two equal halves
\ A ( D ADC ) = A ( D ABC )
\ A ( D ABC ) = A ( D AED )
Test 4 Answer Explanation To Test 4
Answer Explanation To Test 4