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Illustration

\ W = P ´ D V ( D V = V2 - V1 )

Example : CO2 is expanded by supplying 2.343 KJ of heat. If the work done in expansion is 1.4644 KJ calculate the energy change of CO2.

q = + 2.343 KJ W = 1.4644 KJ

\ DE = 2.343 - 1.4644 = 0.8786 KJ

\ Internal energy change, DE = 0.8786 KJ


Example : A gas expanding against a constant pressure of 202.65 KPa from 10 to 20 dm3, absorbs 1255.2 J of heat. Calculate the change in the internal energy of the gas.

  DE = q - W

DE = q - P( V2 - V1 )

= 1255.2 - 202.65 ( 10 - 20 )

= - 3281.7 J.

Index

10.1 Introduction
10.2 First Law of Thermodynamics
10.3 Enthalpy
10.4 Second Law of Thermodynamics
10.5 Gibb's Free Energy
10.6 Absolute Entropies

Chapter 11





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