If 10 dm^{3} of nitrogen gas originally at 20.26 KPa is
allowed to reach a pressure of 40.52 KPa while keeping temperature
constant, final volume can be calculated as follows :
P_{1} = 20.26 KPa P_{2} = 40.52 KPa
V_{1} = 10 dm^{3}
V_{2} = ?
According to Boyle's Law
= 5 dm3
It can be seen that since volume and pressure are inversely proportional, on increasing pressure, the volume decreases.
Example :
The volume of a certain gas at constant temperature was found to be 14 liters when the pressure was 1.2 kg/ cm^{2} If the pressure is decreased by 30% find the final volume of the gas.
V_{1} = 14 liters P_{1} = 1.2 kg/cm2
V_{2} = ? P_{2} = P_{1}  30%
According to Boyle's law
P_{1}V_{1} = P_{2}V_{2 }
The final volume of the gas is 20 liters.
