Areas of two similar triangles are 144 sq.cm. and 81 sq.cm. If one side of the first triangle is 6 cm then find the corresponding side of the second triangle.
= 4.5 c.m.
The side of an equilateral triangle ABC is 5 cm.
Find the length of the side of another equilateral D
PQR whose area is four times area of D
Since both triangles are equilateral they are similar.
The corresponding sides of two similar triangles are 4 cm and 6 cm. Find the ratio of the areas of the triangles.
D ABC ~ D PQR such that l (seg.AB) : l (seg.PQ) that is 8 : 6. If area of D ABC is 48 sq.cm what is the area of the smaller triangle.
In a trapezium ABCD, side AB çç CD. The diagonals AC and BD cut each other at M.
To Prove that
AMB and D CMD.
Ð CMD, vertical angles
Ð DCM alternate angles
\ By AA test
AMB ~ D