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iv) Area from -2.18 to - 1.35 is the same from 1.35 to 2.18.

P ( -2.18 £ z £ -1.35 ) = 0.4854 - 0.4115

= 0.0739 i.e. » 7% of area.

v)         Required area = 0.5 - Area between z = 0 to z = 0.6
           (to the left of -0.6)

             = 0.5 - P ( o £ z £ 0.6 )

             = 0.5 - ( 0.2257 )

             = 0.2743 » 27% of area.


vi) Required area = (Area between z = 0 and z = -1.28) + 0.5

       = (Area between z = 0 and z = -1.28) + 0.5

       = 0.3997 + 0.5

       = 0.8997 » 90% of area.


vii) Area from - 2.18 to 0 is the same as

from 0 to 2.18 which is

P ( -2.18 £ z £ 0 )

= P ( 0 £ z £ -2.18) = 0.4864

and area from 0 to 1.35 is

P ( 0 £ z £ -1.35) = 0.4115

Thus the required area is the sum of two

i.e. P (-2.18 £ z £ -1.35) = 0.4854 + 0.4115

= 0.8969 » 90% of area

[next page]

Index

7. 1 Introduction
7. 2 Trial
7. 3 Sample Space
7. 4 Definition of Probability
7. 5 The Laws of Probability
7. 6 Conditional Probability
7. 7 Theoretical Distribution
7. 8 Binomial Distribution
7. 9 Normal Distribution

Chapter 8





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