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SOLVED PROBLEMS
 In D ABC, Ð
B = 90^{0}, BC = 1, AC = 2. Find Ð
A, ÐC and AB.
Solution
cos C =
cos C = cos 60^{0} ..... [From
the table]
\Ð C = 60^{0}
\Ð A = 60^{0}
and by the Pythagoras theorem, AB^{2} = AC^{2}  BC^{2}

Triangle ABC is isosceles with Ð
B = Ð C = p
/ 6 rad. AD is the median meeting BC in point D. Find AD and
AB. Given that BC = 6 cms.
Solution
SinceÐ B =Ð
C= p / 6 rad = 30^{0}
Since D ABC is an isosceles triangle,
median AD is perpendicular to side BC
Also BD = DC = 3 cm and Ð BAD =
Ð CAD = 60^{0}

Index
2.1 Trigonometric Ratio of Acute Angles
2.2 Fundamental Relation between the trigonometric Ratios of an angle
2.3 Functions of General Angles or t Ratio
2.4 Tables of Trigonometric Function
Supplementary Problems
Chapter 3
