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Illustration

Solve the right triangle ABC, if hypotenuse c = 6 and b = 3.

Solution

We have a2=c2 - b2\ a2=62-b2 \ a2 = (6)2 - (3)2 \ a2=27

(II) Two sides other than hypotenuse being given

Illustration

Solve the right triangle PQR, Given that r = 8, p = 5.

Solution :

(III) One angle (other than right angle) and its opposite side being known.


Illustration

Solve triangle LMN, Ð M = 900, Ð L = 300 and l = 10

Solution : In triangle LMN, Ð N = 900 - Ð L \ Ð N = 900 - 300 = 600

(IV) One angle (other than right angle) and its adjacent side is being given.

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Index

3. 1 Solving Right Triangles
3. 2 Law of Cosines
3. 3 Law of Sines
3. 4 The Ambiguous Case of Law of Sines
3. 5 Areas of Triangles
Supplementary Problems

Chapter 4





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