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2. Find the difference between the largest and smallest angles of a triangle if the lengths of sides are 10, 19 and 23.

Solution

The angle opposite to the largest side is the largest angle. (...a=23(largest)) \ Ð A is the largest angle.

Thus, the difference between the largest and smallest angles is 100^{0} 18' - 25^{0}.20' = 74^{0} 58'

3. If in DABC, a=4, b = 5 and c = 6. Show that Ð C = 2 Ð A

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Index

3. 1 Solving Right Triangles 3. 2 Law of Cosines 3. 3 Law of Sines 3. 4 The Ambiguous Case of Law of Sines 3. 5 Areas of Triangles Supplementary Problems

Chapter 4