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Example 1

Find the equation of the tangent and normal to the curve y = 3x2 - 4x -2 at the point (1, -3)

Solution : y = 3x2 - 4x -2 ® The curve.

By Differentiating w. r. to x, we get

\ Equation of the tangent at point P (1, -3) is

y - (-3) = 2 (x - 1)

i.e. y + 3 = 2x -2

i.e. y = 2x -5

Next, slope of the normal at

\ Equation of the normal at P (1, -3) is

i.e. 2 (y + 3) = - (x - 1)

i.e. x + 2y + 5 = 0

[next page]

 

Index

5.1 Tangent And Normal Lines
5.2 Angle Between Two Curves
5.3 Interpretation Of The Sign Of The Derivative
5.4 Locality Increasing Or Decreasing Functions 5.5 Critical Points
5.6 Turning Points
5.7 Extreme Value Theorem
5.8 The Mean-value Theorem
5.9 First Derivative Test For Local Extrema
5.10 Second Derivative Test For Local Extrema
5.11 Stationary Points
5.12 Concavity And Points Of Inflection
5.13 Rate Measure (distance, Velocity And Acceleration)
5.14 Related Rates
5.15 Differentials : Errors And Approximation

Chapter 6





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